Since the first object is resting on a smooth horizontal table, the only horizontal force acting on it is the tension of the string.Using Newton's second law ( ) for the first object: T=m1⋅acap T equals m sub 1 center dot a Substitute the known values:
The second object is hanging and moving downward with the same acceleration . The forces acting on it are: Gravitational force acting downward: Tension acting upward: Applying Newton's second law for the downward motion: teen streap
m2⋅g−m2⋅a=Tm sub 2 center dot g minus m sub 2 center dot a equals cap T Since the first object is resting on a
m2=0.610−2.0m sub 2 equals the fraction with numerator 0.6 and denominator 10 minus 2.0 end-fraction m2=0.68.0m sub 2 equals 0.6 over 8.0 end-fraction m2=0.075 kgm sub 2 equals 0.075 kg 🏁 Final Answer The tension in the string is and the mass of the second object is teen streap