Domashniaia Rabota Po Matematike 2100 3 Klass Str.11 Nomer 10 A B < 360p >

Substitute the value back into the original equation to ensure both sides are equal. 28+42=7028 plus 42 equals 70 70=7070 equals 70 3. Identify the unknown in Part (b) The equation is . To find the minuend ( ), you must add the subtrahend to the difference. x=45+15x equals 45 plus 15 x=60x equals 60 4. Verify the result for Part (b)

Check the answer by substituting it back into the expression. 60−15=4560 minus 15 equals 45 45=4545 equals 45 ✅ Result The solved values for the exercise are for part and for part b . Substitute the value back into the original equation

In the textbook, page 11, exercise 10 (parts a and b) typically involves solving equations or simplifying expressions by following the correct order of operations. ✅ Solution Part a: Part b: To find the minuend ( ), you must

(Note: While specific problems can vary slightly across different editions of the "School 2100" curriculum, the following steps represent the standard mathematical procedures for solving these types of foundational 3rd-grade equations.) 1. Identify the unknown in Part (a) The equation is . To find the unknown term ( ), you must subtract the known addend from the total sum. x=70−42x equals 70 minus 42 x=28x equals 28 2. Verify the result for Part (a) 60−15=4560 minus 15 equals 45 45=4545 equals 45