Klass Ershova Goloborodko Reshenie C20a 1 Str | Algebra I Nachala Analiza 10-11

log0.5(x+1)≥-2log base 0.5 of open paren x plus 1 close paren is greater than or equal to negative 2 The argument must be positive:

), so the logarithmic function is decreasing. When removing the logs, we must the inequality sign: x+1≤4x plus 1 is less than or equal to 4 x≤3x is less than or equal to 3 3. Combine with the domain Combining , we get the interval ✅ Answer : Problem 3: Solve the inequality

log2(2x−4)>log2(8)log base 2 of open paren 2 x minus 4 close paren is greater than log base 2 of 8 Since the base

For the logarithm to be defined, its argument must be strictly positive: 2x−4>02 x minus 4 is greater than 0 2x>42 x is greater than 4 x>2x is greater than 2