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While the CodeHS exercise often requires the manual loop approach above, the simplest way to do this in standard Python is using the .replace() method:

: word[:index] takes everything before the letter, and word[index + len(letter):] takes everything after it. Adding them together effectively "deletes" the unwanted part. 7.6 / 10 123...

def remove_all_from_string(word, letter): return word.replace(letter, "") Use code with caution. Copied to clipboard While the CodeHS exercise often requires the manual

: The while True ensures the code keeps searching until every instance is gone, which is necessary if the letter appears multiple times (e.g., removing "na" from "banana"). Alternative (Standard Python) Copied to clipboard : The while True ensures

The prompt likely refers to from the CodeHS Python curriculum. This exercise requires you to write a function that removes every instance of a specific "letter" (or substring) from a given word. Correct Python Implementation

def remove_all_from_string(word, letter): # If the letter to remove is empty, return the original word if letter == "": return word while True: # Find the first occurrence of the letter index = word.find(letter) # If .find() returns -1, the letter is no longer in the string if index == -1: return word # Rebuild the string by skipping the found instance word = word[:index] + word[index + len(letter):] # Example usage: # word = input("Enter word: ") # letter = input("Enter letter to remove: ") # print(remove_all_from_string(word, letter)) Use code with caution. Copied to clipboard Breakdown of the Code

: If letter is an empty string, the loop would run forever; we return the original word immediately.